Author Topic: a^2 + b^2 = c^2  (Read 6177 times)

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Offline Quantum Burrito

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Re: a^2 + b^2 = c^2
« Reply #15 on: June 20, 2006, 11:56:14 pm »
a, b, and c have to be positive and n > 2

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Offline Clayface

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Re: a^2 + b^2 = c^2
« Reply #16 on: June 21, 2006, 12:00:57 am »
well that only works with multiples of 3,4,and 5 plugged into a,b,and c respectably,

so
3^2+4^2=5^2
6^2+8^2=10^2
. . . .
. . . .
45^2+60^2=75^2
ect,

if you try plugging in any numbers that dont follow that pattern, it wont work.

those are all the numbers that satisfy the equation, as I stated before, I just posted an example of how the equation doesnt work with all numbers.

and @ quantum Burrito, how did I not read right?
all the numbers I used follow'd the outline.


sorry for bad termanology / spelling

Offline Genesis

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Re: a^2 + b^2 = c^2
« Reply #17 on: June 21, 2006, 12:05:40 am »
n > 2

What will you do?

Offline Clayface

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Re: a^2 + b^2 = c^2
« Reply #18 on: June 21, 2006, 12:17:32 am »
it is > 2

Offline Genesis

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Re: a^2 + b^2 = c^2
« Reply #19 on: June 21, 2006, 12:19:49 am »
OK, I've officialy lost you, what problem are you doing exactly?

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Offline Daxx

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Re: a^2 + b^2 = c^2
« Reply #20 on: June 21, 2006, 12:21:46 am »
it is > 2

Dear god, and you claim to be two years advanced in maths?

Offline Clayface

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Re: a^2 + b^2 = c^2
« Reply #21 on: June 21, 2006, 12:24:49 am »
gahhhh

screw off, all of you,

I cant think straight.
 :-[ :-X :-[

havn't been in school in like a month.

Offline Oviraptor

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Re: a^2 + b^2 = c^2
« Reply #22 on: June 22, 2006, 12:29:55 pm »
Fermat's last theorum, eh?

http://math.stanford.edu/~lekheng/flt/wiles.pdf

What he said.

Offline stuck

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Re: a^2 + b^2 = c^2
« Reply #23 on: June 22, 2006, 02:40:18 pm »
arrgh.. Oviraptor beat me to it. >:(
Yea, what he said.

I think there was a 200 page proof for this.

Offline Aybraus

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What now!
« Reply #24 on: June 22, 2006, 05:43:42 pm »
I challenge you to prove that, only knowing that r2π=Acircle, prove that dπ=C

π being pi incase you can't load up unicode.
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Offline Genesis

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Re: a^2 + b^2 = c^2
« Reply #25 on: June 23, 2006, 11:26:21 am »
Y'know, I just KNEW that Oviraptor would be the one to ruin my fun with this.   :D
Don't worry, I'm not mad, I might have been if you didn't know better though....

Good job!

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Offline stuck

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Re: a^2 + b^2 = c^2
« Reply #26 on: June 23, 2006, 03:52:24 pm »
Ok, I'll have a crack at it.

On second thought, you need to also know some axioms such as the relationship between a regular polygons area and perimeter.

So that is: kl2 = k2l

k is a constant depending on the number of sides, and l is a side length.

We see that Kl2 = (pi)r2 in this case.

Therefore, we set K = pi and l = r; If you want to make l = diameter, then k = (pi)/2

Substitute this in for the other equation (transitive property, I think. Three years since geometry and proofs) and you get 2(pi)r = C.


I think I just made up some rules, but feel free to approve of this. Then again, you may need some calculus to really prove it. Calculus which I don't have.

EDIT: This basic rule should work (the axiom that I outlined) with regular polygons. It works with rectangles (k = 1), triangles, though, is on shaky footing. But I know there is a formal relation somewhere.

EDITEDIT: triangles k is sqr(3)/4
« Last Edit: June 24, 2006, 07:21:18 pm by stuckin2004 »

Offline Aybraus

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Re: a^2 + b^2 = c^2
« Reply #27 on: June 25, 2006, 04:16:19 pm »
My chalange still stands.
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