### Author Topic: a^2 + b^2 = c^2  (Read 8648 times)

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#### Quantum Burrito ##### Re: a^2 + b^2 = c^2
« Reply #15 on: June 20, 2006, 11:56:14 pm »
a, b, and c have to be positive and n > 2 Quote from: The Will
In a movie, one can always pull back and condemn the character or the artist ... But in playing a game ... we can be encouraged to examine our own values by seeing how we behave within virtual space.
tl;dr. But with all those shiny symbols and numbers it's probably awsome.

#### Clayface ##### Re: a^2 + b^2 = c^2
« Reply #16 on: June 21, 2006, 12:00:57 am »
well that only works with multiples of 3,4,and 5 plugged into a,b,and c respectably,

so
3^2+4^2=5^2
6^2+8^2=10^2
. . . .
. . . .
45^2+60^2=75^2
ect,

if you try plugging in any numbers that dont follow that pattern, it wont work.

those are all the numbers that satisfy the equation, as I stated before, I just posted an example of how the equation doesnt work with all numbers.

and @ quantum Burrito, how did I not read right?
all the numbers I used follow'd the outline.

sorry for bad termanology / spelling #### Genesis

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• Greetings. ##### Re: a^2 + b^2 = c^2
« Reply #17 on: June 21, 2006, 12:05:40 am »
n > 2

#### Clayface ##### Re: a^2 + b^2 = c^2
« Reply #18 on: June 21, 2006, 12:17:32 am »
it is > 2 #### Genesis

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• Greetings. ##### Re: a^2 + b^2 = c^2
« Reply #19 on: June 21, 2006, 12:19:49 am »
OK, I've officialy lost you, what problem are you doing exactly?

#### Daxx ##### Re: a^2 + b^2 = c^2
« Reply #20 on: June 21, 2006, 12:21:46 am »
it is > 2

Dear god, and you claim to be two years advanced in maths?

#### Clayface ##### Re: a^2 + b^2 = c^2
« Reply #21 on: June 21, 2006, 12:24:49 am »
gahhhh

screw off, all of you,

I cant think straight.   havn't been in school in like a month. #### Oviraptor ##### Re: a^2 + b^2 = c^2
« Reply #22 on: June 22, 2006, 12:29:55 pm »
Fermat's last theorum, eh?

http://math.stanford.edu/~lekheng/flt/wiles.pdf

What he said. Follow: The Rules Visit: Vvukkrauur Where am I? GamingSteve Wiki #### stuck ##### Re: a^2 + b^2 = c^2
« Reply #23 on: June 22, 2006, 02:40:18 pm »
arrgh.. Oviraptor beat me to it. Yea, what he said.

I think there was a 200 page proof for this.

#### Aybraus ##### What now!
« Reply #24 on: June 22, 2006, 05:43:42 pm »
I challenge you to prove that, only knowing that r2π=Acircle, prove that dπ=C

π being pi incase you can't load up unicode.
I'm toothy22 on Steam. Someone needs to invite me into the GS clan!

#### Genesis

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• Greetings. ##### Re: a^2 + b^2 = c^2
« Reply #25 on: June 23, 2006, 11:26:21 am »
Y'know, I just KNEW that Oviraptor would be the one to ruin my fun with this. Don't worry, I'm not mad, I might have been if you didn't know better though....

Good job!

#### stuck ##### Re: a^2 + b^2 = c^2
« Reply #26 on: June 23, 2006, 03:52:24 pm »
Ok, I'll have a crack at it.

On second thought, you need to also know some axioms such as the relationship between a regular polygons area and perimeter.

So that is: kl2 = k2l

k is a constant depending on the number of sides, and l is a side length.

We see that Kl2 = (pi)r2 in this case.

Therefore, we set K = pi and l = r; If you want to make l = diameter, then k = (pi)/2

Substitute this in for the other equation (transitive property, I think. Three years since geometry and proofs) and you get 2(pi)r = C.

I think I just made up some rules, but feel free to approve of this. Then again, you may need some calculus to really prove it. Calculus which I don't have.

EDIT: This basic rule should work (the axiom that I outlined) with regular polygons. It works with rectangles (k = 1), triangles, though, is on shaky footing. But I know there is a formal relation somewhere.

EDITEDIT: triangles k is sqr(3)/4
« Last Edit: June 24, 2006, 07:21:18 pm by stuckin2004 »

#### Aybraus ##### Re: a^2 + b^2 = c^2
« Reply #27 on: June 25, 2006, 04:16:19 pm »
My chalange still stands.
I'm toothy22 on Steam. Someone needs to invite me into the GS clan!